将while循环转换为.forEach会产生意想不到的结果

在如何使用多个属性对对象数组进行排序的有用示例中，执行排序的代码使用了while循环(请参阅下面代码片段中的students1)。我试图通过使用。 foreach简化while循环，但得到一个不同的结果集(见学生s2)。在使用。forEach进行重构时哪里出了问题，它没有给出与while循环相同的输出？

const students = [
    {
        firstName: 'John',
        lastName: 'Appletree',
        grade: 12
    },
    {
        firstName: 'Mighty',
        lastName: 'Peachtree',
        grade: 10
    },
    {
        firstName: 'Kim',
        lastName: 'Appletree',
        grade: 11
    },
    {
        firstName: 'Shooter',
        lastName: 'Appletree',
        grade: 12
    },
    {
        firstName: 'Peter',
        lastName: 'Peachtree',
        grade: 12
    }
];
const sortBy = [
    {
      prop:'grade',
      direction: -1
    },
    {
      prop:'lastName',
      direction: 1
    }
];
const students1 = JSON.parse(JSON.stringify(students));
const students2 = JSON.parse(JSON.stringify(students));
students1.sort((a, b) => {
  let i = 0, result = 0;
  while (i < sortBy.length && result === 0) {
    const prop = sortBy[i].prop;
    const direction = sortBy[i].direction;
    result = direction *
        (
             a[prop].toString() < b[prop].toString() ? -1 :
            (a[prop].toString() > b[prop].toString() ? 1 : 0)
        );
    i++;
  }
  return result;
});
students2.sort((a, b) => {
  let result = 0;
  sortBy.forEach(o => {
    result = o.direction *
    (
         a[o.prop].toString() < b[o.prop].toString() ? -1 :
        (a[o.prop].toString() > b[o.prop].toString() ? 1 : 0)
    );
  });
  return result;
});
console.log(students);
console.log('one', students1);
console.log('two', students2);

# # #你forEach and 和while loop循环并不是等价的。如果while condition was just i < sortBy.l条件是i < sortBy.length then it would work.然后它就会起作用。这里有一个附加条件result === 0 which forEach doesn't account for.

const students = [
    {
        firstName: 'John',
        lastName: 'Appletree',
        grade: 12
    },
    {
        firstName: 'Mighty',
        lastName: 'Peachtree',
        grade: 10
    },
    {
        firstName: 'Kim',
        lastName: 'Appletree',
        grade: 11
    },
    {
        firstName: 'Shooter',
        lastName: 'Appletree',
        grade: 12
    },
    {
        firstName: 'Peter',
        lastName: 'Peachtree',
        grade: 12
    }
];
const sortBy = [
    {
      prop:'grade',
      direction: -1
    },
    {
      prop:'lastName',
      direction: 1
    }
];
const students1 = JSON.parse(JSON.stringify(students));
const students2 = JSON.parse(JSON.stringify(students));
students1.sort((a, b) => {
  let i = 0, result = 0;
  while (i < sortBy.length && result === 0) {
    const prop = sortBy[i].prop;
    const direction = sortBy[i].direction;
    result = direction *
        (
             a[prop].toString() < b[prop].toString() ? -1 :
            (a[prop].toString() > b[prop].toString() ? 1 : 0)
        );
    i++;
  }
  return result;
});
students2.sort((a, b) => {
  let result = 0;
  sortBy.forEach(o => {
    if (result !== 0) return;
    result = o.direction *
    (
         a[o.prop].toString() < b[o.prop].toString() ? -1 :
        (a[o.prop].toString() > b[o.prop].toString() ? 1 : 0)
    );
  });
  return result;
});
console.log(students);
console.log('one', students1);
console.log('two', students2);