我正在向谷歌安全浏览API发送请求。我相信我正确地遵循了他们的文档。我试过重新生成我的密钥。
我正在发送下面的请求
POST https://safebrowsing.googleapis.com/v4/threatMatches:find?key=AIxxxxxxxxxxxxxxxxxxxxxxxxxxxxxx HTTP/1.1
User-Agent: Fiddler
Host: safebrowsing.googleapis.com
Content-Length: 511
{
"client": {
"clientId": "yourcompanyname",
"clientVersion": "1.5.2"
},
"threatInfo": {
"threatTypes": ["MALWARE", "SOCIAL_ENGINEERING"],
"platformTypes": ["WINDOWS"],
"threatEntryTypes": ["URL"],
"threatEntries": [
{"url": "http://www.urltocheck1.org/"},
{"url": "http://malware.testing.google.test"},
{"url": "http://www.urltocheck2.org/"},
{"url": "http://www.urltocheck3.com/"}
]
}
}
并得到一个空的响应,这不是我期望的与url提供和遵循他们的例子。
HTTP/1.1 200 OK
Content-Type: application/json; charset=UTF-8
Date: Wed, 08 Sep 2021 15:05:59 GMT
Server: scaffolding on HTTPServer2
Cache-Control: private
X-XSS-Protection: 0
X-Frame-Options: SAMEORIGIN
X-Content-Type-Options: nosniff
Alt-Svc: h3=":443"; ma=2592000,h3-29=":443"; ma=2592000,h3-T051=":443"; ma=2592000,h3-Q050=":443"; ma=2592000,h3-Q046=":443"; ma=2592000,h3-Q043=":443"; ma=2592000,quic=":443"; ma=2592000; v="46,43"
Accept-Ranges: none
Vary: Accept-Encoding
Content-Length: 3
{}
https://transparencyreport。google。com/safe-browsing/search?url=malware。testing。google。test
https://developers。google。com/safe-browsing/v4/lookup-api